What’s with the “S” in SCFM

So many times, when reviewing the air requirements for our products, I am met with psi. “I have 100 psi running to this Super Air Knife, but it has almost no air flow”. PSIG and SCFM work hand in hand, and both are critical in optimal performance of our products. These two measurements are related, but they are not immediate family. PSI is more about power, whereas SCFM is more about flow and consistency. When they both combine, force is the outcome. We need both PSI and SCFM to produce force and for products to perform. It seems that most have a solid grasp on PSIG, but the SCFM tends to cause some confusion. Mostly the “S” in the SCFM.

Once we redirect the conversation to SCFM, we almost always find the heart of the issue. But SCFM can be confusing and many times is mistakenly interchanged with CFM. CFM is the easiest to explain, so let’s start there.

CFM is Cubic Feet per Minute of airflow. This is exactly as it sounds, 1 CFM = 1 12″x12″x12″ box full of air moving through the product (Air Knife, Nozzle, Vortex Tube, Air Wipe and so on) per minute. To visualize this, take a look at your office (or visualize one). Let’s say it is 12x12x8 feet, like the sample to the right. That is 1152 cubic feet of air inside that office. If we used a 48″ Super Air Knife, running at 80 psig, it will consume 139.2 standard cubic feet of air per minute, or in other words, it will use all of the air in that office in 8.27 minutes. Assuming that air was not replaced, the Super Air Knife would starve and not have any airflow even though your gauge may still show 80 PSIG. So, when we break it down to this simple form and example, CFM is pretty easy to comprehend.

Now the confusing part: what is the S in SCFM? The S simply stands for Standard. I know, this is shocking, but what is “Standard”? Standard represents values that are a baseline of measurement, even though few of us reside or work in these “ideal” surroundings. Air volume can be altered by several things, the most common are atmospheric pressure, temperature, and relative humidity.

Some genius somewhere decided that the best place to measure for a Standard CFM at sea level. I imagine they chose Key West Florida, on the beach, which sits around 14.7 psia atmospheric pressure. Then, to be precise they measured this when the thermostat read 68°F, and the hygrometer showed 0% relative humidity. Outside of creating a lab with these settings, that beach, on that day, at that precise time, is where you can get a true CFM of air equal to the Standard.

To summarize the “S” or Standard conditions are 14.7 psi atmospheric pressure, 68°F, and 0% relative humidity.

Since most of us will never work in that exact environment, SCFM is “mostly” accurate. This is the reference point that we all can use, and has become the “Standard” across the globe. As you can imagine, it would be impossible for companies such as mine to publish or calculate every Actual CFM (ACFM). But we can do this…

ACFM is just what is says – the exact CFM that you will use based upon your elevation (atmospheric Pressure), your temp, and your relative humidity. I have a peer that wrote a recent blog that goes into depth on this topic as well as ACFM and ICFM (Inlet) and how to calculate each of these. You can see that blog here.

Thank you again for stopping by to find out more about the S in SCFM. If you have any questions about this, or anthing else related to our products, please do not hesitate to reach out.

Thank you for stopping by,

Brian Wages

Application Engineer

EXAIR Corporation
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Cover photo by PIRO4D, and licensed by Pixabay

Calculating CFM of Air Needed for Cooling

It’s easy to know that EXAIR’s Vortex Tubes can be used to cool down parts and other items, but did you know that our other engineered compressed air products can be used to cool down these same things? It’s the same process as cooling down hot food by blowing on it. And we can use the physical properties of any material – whether it’s the massive billets of steel in the photo up top, or the bowl of soup to the right, to calculate the amount of air flow required to change a certain mass of the material from one temperature to another.

For any material, there’s a certain amount of energy required to cause a certain temperature change of a certain mass of the material. This property is called Specific Heat (Cp), and it’s commonly expressed in Joules per gram per degree Celsius (J/g°C), or Btu’s per pound (mass) per degree Fahrenheit. (Btu/lbm°F). The Specific Heat of the material allows us to calculate the amount of heat that has to be removed to cool it from its starting to its desired temperature, using a standard heat transfer equation:

q = mCp ΔT, where:

  • q is the amount of energy it’ll take to cause the temperature change.
  • m is the mass of the material that you want to change the temperature of.
  • Cp is the Specific Heat we talked about above.
  • ΔT is the starting temperature, minus the desired temperature.

Once we know the amount of heat to be removed, we can then apply units of time, and calculate the rate of cooling you’ll need to achieve in order to get the material to the temperature you want, in the time that you want. Let’s work through an example, using a piece of steel weighing 50lbs that needs to be cooled from 300 °F to 200°F:

q = m * Cp * ΔT, where:

  • m = 50lbm
  • Cp = 0.117 Btu/lbm°F
  • ΔT = 300°F – 200°F = 100°F
  • q = 50lbm * 0.117 Btu/lbm°F * 100°F = 585 Btu of energy (heat) to be transferred

Now, let’s say we have two minutes to cool this piece of steel:

585 Btu/2 minutes X 60 minutes/hr = 17,550 Btu/hr

That’s the rate of cooling required for this application. Now, we can use another equation that’s commonly used in the HVAC industry to determine the amount of room temperature (70°F) air flow that’ll remove that amount of heat. It’s called the cooling power formula:

Q̇ = 1.0746 * ΔT * ṁ, where:

  • Q̇ is the rate of heat transfer
  • 1.0746 is a constant
  • ΔT is the difference between the desired temperature and the air temperature
  • ṁ is the flowrate of air in cubic feet per minute

Since “Q̇” is the unknown value, we have to get to use a little algebra and rearrange the equation:

ṁ = Q̇/(1.0746 * ΔT), where:

  • Q̇ = 17,550 Btu/hr
  • 1.0746 = 1.0746 (remember, it’s a constant)
  • ΔT = 100°F – 70°F = 30°F
  • 17,550 Btu/hr/(1.0746 * 30°F) = 544.4 cubic feet per minute

Now, this assumes that equilibrium will be reached (i.e. all of the heat than CAN be transferred to the air flowing past the steel WILL be transferred), but that’s not going to happen. Depending on the geometry of the material to be cooled, there are ways to maximize the contact time between the material and the cooling medium. For example, constructing a tunnel over a section of a conveyor so the airflow can blow in the opposite direction that the material is traveling. Even then, though, it’s unlikely you’ll reach equilibrium, so we’ll apply a service factor, and say our airflow is going to be 30% efficient in cooling the steel (which is really quite high) so we’ll need:

544.4 CFM/0.3 = 1,815 CFM

EXAIR Air Amplifiers are an excellent option for providing this kind of cooling flow. They’re compact, quiet, and efficient. Using the following table, we see that a 3″ Adjustable Air Amplifier supplied at 80psig has a total developed flow rate (Air Volume at Outlet) of 774 SCFM:

So, three of them will generate a total cooling flow of 2,322 SCFM, and that’s not counting the air entrained in the immediate discharge (Air Volume at 6″). That’s even more than we THINK we need…but that can be adjusted and/or regulated.

Another thing I like about the Adjustable Air Amplifiers for an application like this is that they’re, well, adjustable (it’s right there in the name). Turning the exhaust plug in or out will decrease or increase the air flow – this is how you can make gross adjustments to the air flow. A Pressure Regulator in the supply line then allows for precise ‘tweaks’ so you can dial in the performance to the level you need, without using any more compressed air than you have to.

With sixteen distinct models to choose from, EXAIR Air Amplifiers are a quick and easy way to provide a tremendous amount of cooling air flow from a compact, lightweight product.

If you have any questions about using compressed air for cooling, give me a call.

Russ Bowman, CCASS

Application Engineer
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